Ubuntu 14.04.1.

I have a bash script, called by cron every 10 minutes, which basically looks for files in a subdir, then loops through and process each file. But how do I check if there are no files found? If there are no files found I don't want to process them, and I don't want to get an email via cron that says "no files found", because cron runs every 10 minutes. That's 144 emails per day saying "no files found" that I don't want to get.

• The input/ dir is owned by me and has full rwx permissions.


• I've already guaranteed the files in input/ do not contain spaces, thanks to another answer on Ask Ubuntu.

Here's my basic script.

#!/bin/bash

# Cron requires a full path in $myfullpath

myfullpath=/home/comp/progdir

files=`ls $myfullpath/input/fedex*.xlsx`

# How do I check for no files found here and exit without generating a cron email?

for fullfile in $files

do



done

Thanks! I didn't even know what to google for this one.

EDIT: My script is now this:

#!/bin/bash

# Script: gocronloop, Feb 5, 2015

# Cron requires a full path to the file.

mydir=/home/comp/perl/gilson/jimv/fedex

cd $mydir/input

# First remove spaces from filesnames in input/

find -name "* *" -type f | rename 's/ /-/g'

cd $mydir

shopt -s nullglob

if [ $? -ne 0 ]; then

    echo "ERROR in shopt"

    exit 1

fi

for fullfile in "$mydir"/input/fedex*.xlsx

    do

    # First remove file extension to get full path and base filename.

    myfile=`echo "$fullfile"|cut -d'.' -f1`

    echo -e "

Doing $myfile..."

    # Convert file from xlsx to xls.

    ssconvert $myfile.xlsx $myfile.xls

    # Now check status in $?

    if [ $? -ne 0 ]; then

        echo "ERROR in ssconvert"

        exit 1

    fi

    perl $1 $mydir/fedex.pl -input:$mydir/$myfile.xls -progdir:$mydir 

    done