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AWK counting back

rated 0 times [ 0] [ 0] / answers: 1 / hits: 955 / 3 Years ago, mon, july 19, 2021, 4:14:15

I have a list of domains matched and piped in through grep with various length but all match the last three records. I'm trying to output all of the non-qualified sub-domains.

I have:

awk -F'.' -v OFS='.' '{$(NF-3)=$(NF-2)=$(NF-1)=""; print $0}'

my output leaves trailing ...... on the output

Thanks

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fulerio

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4 Years ago

answered 3 Years ago tocklftime · Accepted Answer

Try substituting them:

$ awk -F'.' 'sub(FS $(NF-2) FS $(NF-1) FS $NF,"")' <<<"www.cse.iitb.ac.in"

www.cse

I'm not sure why this works and your method doesn't, but according to this unix.com post, that's the way.