I have a code snippet that I am using to parse through a log file and print information I need.

for i in $(cat ~/jlog/"$2"); do

        grep "$1" ~/jlog/"$2" |

        awk '/([a-zA-Z0-9.]+/ {print $7}' 

 done;

The problem is when I enter input in, it displays the answer multiple times:

(1.3.51.0.1.1.10.10.30.48.2084865.2084839/1.2.840.113619.2.284.3.17454802.933.1401109176.280.1)

(1.3.51.0.1.1.10.10.30.48.2084865.2084839/1.2.840.113619.2.284.3.17454802.933.1401109176.283.1)

(1.3.51.0.1.1.10.10.30.48.2084865.2084839/1.2.840.113619.2.80.977011700.14346.1401109696.2)

(1.3.51.0.1.1.10.10.30.48.2084865.2084839/1.2.840.113619.2.80.977011700.14346.1401109706.51)

(1.3.51.0.1.1.10.10.30.48.2084865.2084839/1.2.840.113619.2.80.977011700.14346.1401109758.100)

(1.3.51.0.1.1.10.10.30.48.2084865.2084839/1.2.840.113619.2.80.977011700.14346.1401109773.149)

(1.3.51.0.1.1.10.10.30.48.2084865.2084839/1.2.840.113619.2.80.977011700.14346.1401109810.198)

(1.3.51.0.1.1.10.10.30.48.2084865.2084839/1.2.840.113619.2.80.977011700.14346.1401109818.247)

Is there any way I can trim this so I can only have the first series of data display once. I only need 1.3.51.0.1.1.10.10.30.48.2084865.2084839 to print out once.

I tried to change it to this as well, but Bash does not like it:

for i in $(cat ~/jlog/"$2"); do

        grep "$1" ~/jlog/"$2" |

        awk '/([a-zA-Z0-9.]+/' |

        awk -F'[(/]' ' {print $2, exit}'

done;

Then tried this:

for i in $(cat ~/jlog/"$2"); do

        grep "$1" ~/jlog/"$2" |

        awk -F'[(/]' '/([a-zA-Z0-9.]+/ {print $2, exit }'

done;