Question

3

Weird output by declare and array

rated 0 times [ 3] [ 0] / answers: 1 / hits: 2266 / 3 Years ago, sun, september 19, 2021, 4:24:07

I am trying to output the values of array element but I am getting weird output. Please have a look at it and help me solve it. Thank you.

n=2

declare -a myarray[$n]

myarray[0]=hey

myarray[1]=hello

myarray[2]=bye

for i in ${myarray[@]}

do

        echo $i

done

Output:

robin@robin-VirtualBox:~/lx$ sh array.sh

array.sh: 2: array.sh: declare: not found

array.sh: 3: array.sh: myarray[0]=hey: not found

array.sh: 4: array.sh: myarray[1]=hello: not found

array.sh: 5: array.sh: myarray[2]=bye: not found

array.sh: 6: array.sh: Bad substitution

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odenanno

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3 Years ago

answered 3 Years ago teromato · Accepted Answer

declare is a bash shell builtin, and is not defined in the sh shell.

So, you must to run your script using the following command:

bash array.sh

Or add, the following shebang line at the start of your script:

#!/bin/bash

Be sure that your script is exectutable:

 chmod +x array.sh

And run it using the following command:

./array.sh