How can I create a shell script which receives a vector argument like
./script.sh google.com,yahoo.com
and display ip for each domain
like google.com 100.23.123.13
EDIT:
#!/bin/bash
while [ "$1" ];
do
host $1 | grep address | head -1
done
You can use the following script:
#!/bin/sh
for domain in $@; do
host $domain | grep "has address" | awk '{print $1" "$4}'
done
Usage: ./script www.domain1.com domain2.com ...
For example:
$ ./script.sh www.google.com yahoo.com www.askubuntu.com google.ro
www.google.com 173.194.40.81
www.google.com 173.194.40.84
www.google.com 173.194.40.82
www.google.com 173.194.40.83
www.google.com 173.194.40.80
yahoo.com 98.138.253.109
yahoo.com 206.190.36.45
yahoo.com 98.139.183.24
askubuntu.com 198.252.206.24
google.ro 173.194.35.31
google.ro 173.194.35.23
google.ro 173.194.35.24
