Question

5

How to delay the start of an application during startup to reduce total booting time?

rated 0 times [ 5] [ 0] / answers: 1 / hits: 10046 / 2 Years ago, fri, june 24, 2022, 10:50:45

I have an application installed on my Samsung NP-RV509 which makes the Fn keys work properly.

I have determined that the startup of this application is the reason for almost 30 extra seconds of booting time.

Can I write a shell/python script (I, myself, can't actually do this as I don't know shell/python programming) that will introduce a delay by maybe using a loop or something and then start the above application? Shall I add/apply this script in startup apps?

This should effectively simulate the running of that program at startup, but it would be delayed in actuality.

How can I achieve this?

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ainlyyor

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1 Year ago

answered 2 Years ago initiallartebeest · Accepted Answer

You can add a delay time with sleep command.

man sleep for more info .

Example

I want to startup a program with delay of 10 seconds.
I create an entry in the startup applications with this in command field

sleep 10;/usr/bin/<program name>

Example 2

I want to create a script with the delay (sleep) option and add this script to startup applications

gedit delayscript.sh

and I add these lines

#!/bin/bash 



sleep 10 

/usr/bin/<program name>

save the script and give it executable permissions

chmod +x delayscript.sh

and add it to startup applications (command field) with full path

/home/username/delayscript.sh