In a shell script I tried to replace blank space by
with this command
echo -e $var |tr ' ' '
'
Outside the script it workd perfectly but inside there is no effect .
This how i use in the script:
var =$(echo -e $var | tr ' ' '
' )
Thanks .
After expanding a parameter expansion ($var) or command substitution ($(cmd)), the shell removes all whitespace from the expanded result in order to split them into words (word splitting). On top of that, it tries to match filenames for the words that contain *, ? and/or [...] (pathname expansion). So always enclose expansions in double quotes ("$var" and "$(cmd)") to avoid word splitting and pathname expansion to be attempted.
$ var=$'two
lines here'
$ echo $var
two lines here
$ echo "$var"
two
lines here
$
Hence:
echo "$var" | tr ' ' '
'
# or using bash's more powerful types of parameter expansions
echo "${var// /$'
'}"
var="$(echo "$var" | tr ' ' '
')"
See also: http://mywiki.wooledge.org/Quotes
