Question

5

PyGTK: Opening Links in Default Web Browser

rated 0 times [ 5] [ 0] / answers: 1 / hits: 2618 / 3 Years ago, thu, july 22, 2021, 1:55:20

Is there a way to create a Gtk.Button("http://www.google.com"), when clicked will open the system default Web Browser using the label as the URL?

What I could do is...

import os

button = Gtk.Button(label="http://www.google.com")

label = button.get_text()

os.system("sensible-browser " + label)

The above code does what I need it to do. Is this the correct way about doing this? Or is there a GTK function I should be using instead?

(Disclaimer: I am usually more specific with my questions, I feel like this is really basic and may not even be possible and I have checked the docs. Thank you!)

Answers

Only authorized users can answer the question. Please sign in first, or register a free account.

ravturtl

Add To Favorites

Follow

Total Points: 335

Total Questions: 132

Total Answers: 110

Location: Tanzania

Member since Wed, Feb 24, 2021

3 Years ago

answered 3 Years ago ardtry · Accepted Answer

Two solutions in one! :)

First, there is a special button widget just for this job: GtkLinkButton. You create a GtkLinkButton just like a normal button. Here is a simple example program written with Python and PyGObject. PyGTK should look pretty similar:

from gi.repository import Gtk

window = Gtk.Window()

button = Gtk.LinkButton("http://www.google.com", label="google.com")

window.add(button)

window.show_all()

Gtk.main()

As an alternative, you can directly call the function gtk_show_uri.

If you need more sophisticated application launching stuff, take a look at Gio.