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1

Using shell find all sub-directories that contain certain files

rated 0 times [ 1] [ 0] / answers: 1 / hits: 6817 / 2 Years ago, fri, march 4, 2022, 12:09:46

I am trying to use shell to find all sub-directories in any directory. What I would want is to have a .sh file (shell script file) that can receive as a parameter the name of the directory I'm interested in and the list of files I want to find (NOTE: I want only sub-directories that have all these files).

I know I can use this:

find $D -perm -u=rx -type f

Where D is the directory, -u is the user, r is the users right to read and x is the right to modify I believe, but uhm I have no idea how to make the file accept parameters and I have no idea how to use -u=rx

EDIT: I now understand how to use parameters for a shell script file, so that's ok. I still don't get most of the rest.

I would love it if someone could either explain the code I mentioned or ... give an alternative ?

I'm also ok with a partial answer, I just need some help.

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olouredping

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3 Years ago

answered 2 Years ago sconhoney · Accepted Answer

I would interpret your requirements as "find all subdirectories which contain all the specific files"

#!/bin/bash

parent_dir="$1"

shift

find "$parent_dir" -type d |

while IFS= read -r subdir; do

  all_present=true

  for file in "$@"; do

    if [[ ! -f "$subdir/$file" ]]; then

      all_present=false

      break

    fi

  done

  $all_present && echo "$subdir"

done

the "IFS=" and "read -r" parts ensure the value of "dir" contains the actual directory name even if it includes spaces or special characters.