Please see the dd command and the output below.

dd if=/dev/null of=./VirtualDisk.img bs=1M count=1024  

0+0 records in   

0+0 records out   

0 bytes copied, 0.000281296 s, 0.0 kB/s   

I expected 1024 blocks of size 1MB will be written to the output file. But why is the output file size of VirtualDisk.img 0?

Also, see another example.

dd if=/dev/null of=./VirtualDisk.img bs=1M seek=1024

0+0 records in

0+0 records out

0 bytes copied, 0.000254032 s, 0.0 kB/s

According to the manual, is should skip 1024 blocks of size 1MB from the start of output file. But the generated output file size of VirtualDisk.img is 1073741824 (1MB * 1024). I could see the skipped region was filled with zero.

THis is the dd manual : https://man7.org/linux/man-pages/man1/dd.1.html

To me, the behavior for count and seek is different from what the manual says. How should I absorb this behaviour?