Question

3

find -exec grep in series with an inverted grep, find nested grep

rated 0 times [ 3] [ 0] / answers: 1 / hits: 938 / 2 Years ago, tue, may 3, 2022, 11:24:25

I have the following three files

**file_01.sh**  

GOOD_word  

bla bla BAD_word  

miao GOOD_word bau  

BAD_word

GOOD_word foo

**file_02.sh**  

GOOD_word yes  

GOOD_word bla bla BAD_word  

GOOD_word bla  

BAD_word

**file_03.sh**  

just BAD_word  

and bla bla

I would like to have the following result:

**“o_file.txt”:**  

./i_dir/file_01.sh:1:GOOD_word  

./i_dir/file_01.sh:3:miao GOOD_word bau  

./i_dir/file_01.sh:5:GOOD_word foo  

./i_dir/file_02.sh:1:GOOD_word yes  

./i_dir/file_02.sh:3:GOOD_word bla

This is what I try so far, but does not work.

find ./dir -type f -exec grep -E -i -H "GOOD_word" {} ; | 

  grep -v “BAD_word” {} ; >> o_file.txt;

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answered 2 Years ago vigorousom · Accepted Answer

You are close - you just need to add -n for the line numbers and remove the second {} so that the grep -v operates on the output of the first grep, rather than on the found files:

$ find ./i_dir -type f -exec grep -E -i -H -n "GOOD_word" {} ; | grep -v "BAD_word"

./i_dir/file_01.sh:1:GOOD_word

./i_dir/file_01.sh:3:miao GOOD_word bau

./i_dir/file_01.sh:5:GOOD_word foo

./i_dir/file_02.sh:1:GOOD_word yes

./i_dir/file_02.sh:3:GOOD_word bla

I'm assuming that you need -E because your "real" GOOD_word is an extended regular expression - if that's not the case, you may omit it (and possibly also the -i flag).

Alternatively, you could do something like this, using bash globstar for the directory descent and awk for the logic:

shopt -s globstar

awk '/GOOD_word/ && !/BAD_word/{print FILENAME,FNR,$0}' OFS=: ./i_dir/**/*