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Calling terminal from shell scripts to display results of commands

rated 0 times [ 0] [ 0] / answers: 1 / hits: 944 / 2 Years ago, wed, october 5, 2022, 9:01:14

I wrote a script to call terminal and run a series of commands. The terminal comes up but no result of the other commands.
I named the file show-services-status.sh dropped it in the home directory and made it executable using chmod +x

show-services-status.sh contain the following commands:

gnome-terminal

echo "Display Manager Status"

sudo systemctl status display-manager.service

echo "System Log Status"

sudo systemctl status syslog.service

Why does the terminal comes up without showing the result of the other commands?

I started terminal manually and executed bash show-services-status.sh it worked but i have to press q on the keyboard before i see the result of the next command. how can this be eliminated?
thanks

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rhaeams

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answered 2 Years ago nstitutencert · Accepted Answer

because all the commands are being run sequentially in the same shell from which you execute the gnome-terminal command - rather than running inside the new gnome-terminal

you can add the --no-pager option to the systemctl commands - see man systemctl

If you want to run the following commands inside the new gnome-terminal, you could wrap them in a shell and pass them as a command string, like:

gnome-terminal -- sh -c '

  echo "Display Manager Status"

  systemctl --no-pager status display-manager.service

  echo "System Log Status"

  systemctl status syslog.service

'

Note that I omitted --no-pager on the final systemctl command in order to hold the terminal open - otherwise it will likely close immediately, before you have time to read the results.