I have the file "test.txt" that contains:
Val1 = '59'
Val2 = '76'
Val3 = '42'
Val4 = '53'
I with this command:
perl -pe "s/^Val2 = '(.*)'/1/" test.txt
I Want:
76
But I obtain:
Val1 = '59'
76
Val3 = '42'
Val4 = '53'
The -p argument is like sed's default print - also like sed, if you want to suppress default print, you would use -n instead.
So you could do
perl -ne "print if s/^Val2 = '(.*)'/1/" test.txt
You could also use a regex match rather than a regex substitute:
perl -lne "print $1 if /^Val2 = '(.*)'/" test.txt
or
perl -nE "say $1 if /^Val2 = '(.*)'/" test.txt
(the backslash is to protect $1 from being expanded by the shell, since the expression is in double quotes to allow use of lieral single quotes in the match).
