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rated 0 times [  7] [ 0]  / answers: 1 / hits: 2595  / 1 Year ago, thu, january 5, 2023, 3:18:56

I have a ton of files named this way: [name]_[phonenumber]_HH-mm-ss_dd-MM-yyyy.mp3.
How can I shift [name] and [phonenumber] to the end of file name, and put the date in the beginning in form of yyyy-MM-dd_HH-mm-ss so I get yyyy-MM-dd_HH-mm-ss_[name]_[phonenumber]?



Here is an actual file name: [Unknown]_[+74999519075]_18-01-36_17-01-2014.mp3



I've tried rename, but due to lack of regexp knowledge I didn't come up with a working solution.


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 Answers
3

This should work:



for i in *mp3; do rename 's/(.+?)_(.+?)_(.+?)-(.+?)-(.+?)_(.+?)-(.+?)-(.+?).mp3/$8-$7-$6_$3-$4-$5_$1_$2.mp3/' "$i"; done


The parentheses capture patterns. The 1st captured match is $1, the 2nd $2 etc. So, the command above:




  • will look for everything up to the first _

  • .+? means match the shortest pattern possible because of the ?,

  • then everything up to the 2nd _ etc.

  • and renames accordingly.



I tested it with:



$ touch [name]_[phonenumber]_HH-mm-ss_dd-MM-yyyy.mp3

$ ls

[name]_[phonenumber]_HH-mm-ss_dd-MM-yyyy.mp3

$ for i in *mp3; do rename 's/(.+?)_(.+?)_(.+?)-(.+?)-(.+?)_(.+?)-(.+?)-(.+?).mp3/$8-$7-$6_$3-$4-$5_$1_$2.mp3/' "$i"; done

$ ls

yyyy-MM-dd_HH-mm-ss_[name]_[phonenumber].mp3

[#25559] Thursday, January 5, 2023, 1 Year  [reply] [flag answer]
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