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rated 0 times [  4] [ 0]  / answers: 1 / hits: 643  / 3 Years ago, mon, september 13, 2021, 10:19:28

I have a command example, 



device list


which gives me all devices with their status as okay or error in the following format



[okay     ]:  you are listening on : 11

[error    ]:  not currently listening: 22

[error    ]:  not currently listening: 33

[okay     ]:  you are listening on : 111


I want to print only devices that has status as okay.



I tried using grep command as 



device list | grep -r 'okay'

device list | grep -r '[okay     ]'

device list | grep -r '^okay'

device list | grep  'okay'


But it didn't print any output.
How can I print the devices with status as okay.



Thanks in advance.


More From » command-line
 Answers
7

You don't have to use -r option with grep in this case, because (look at man grep): 




-r, --recursive

              Read all files  under  each  directory,  recursively,  following

              symbolic  links  only  if they are on the command line.  This is

              equivalent to the -d recurse option.



You also have to redirect and errors from the standard output to be piped by the grep command using 2>&1 redirection:



device list 2>&1 | grep 'okay'


Or you can use |&:



device list |& grep 'okay'

[#26371] Tuesday, September 14, 2021, 3 Years  [reply] [flag answer]
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