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/ 2 Years ago, sun, march 6, 2022, 1:54:43
I have a script which searches all files in multiple subfolders and archives to tar. My script is
for FILE in `find . -type f -name '*.*'`
do
if [[ ! -f archive.tar ]]; then
tar -cpf archive.tar $FILE
else
tar -upf archive.tar $FILE
fi
done
The find command gives me the following output
find . -type f -iname '*.*'
./F1/F1-2013-03-19 160413.csv
./F1/F1-2013-03-19 164411.csv
./F1-FAILED/F2/F1-2013-03-19 154412.csv
./F1-FAILED/F3/F1-2011-10-02 212910.csv
./F1-ARCHIVE/F1-2012-06-30 004408.csv
./F1-ARCHIVE/F1-2012-05-08 190408.csv
But the FILE variable only stores first part of the path ./F1/F1-2013-03-19 and then the next part 160413.csv.
I tried using read with a while loop,
while read `find . -type f -iname '*.*'`; do ls $REPLY; done
but I get the following error
bash: read: `./F1/F1-2013-03-19': not a valid identifier
Can anyone suggest an alternative way?
Update
As suggested in the answers below I updated the scripts
#!/bin/bash
INPUT_DIR=/usr/local/F1
cd $INPUT_DIR
for FILE in "$(find . -type f -iname '*.*')"
do
archive=archive.tar
if [ -f $archive ]; then
tar uvf $archive "$FILE"
else
tar -cvf $archive "$FILE"
fi
done
The output that i get is
./test.sh
tar: ./F1/F1-2013-03-19 160413.csv
./F1/F1-2013-03-19 164411.csv
./F1/F1-2013-03-19 153413.csv
./F1/F1-2013-03-19 154412.csv
./F1/F1-2012-09-10 113409.csv
./F1/F1-2013-03-19 152411.csv
./.tar
./F1-FAILED/F3/F1-2013-03-19 154412.csv
./F1-FAILED/F3/F1-2013-03-19 170411.csv
./F1-FAILED/F3/F1-2012-09-10 113409.csv
./F1-FAILED/F2/F1-2011-10-03 113911.csv
./F1-FAILED/F2/F1-2011-10-02 165908.csv
./F1-FAILED/F2/F1-2011-10-02 212910.csv
./F1-ARCHIVE/F1-2012-06-30 004408.csv
./F1-ARCHIVE/F1-2011-08-17 133905.csv
./F1-ARCHIVE/F1-2012-10-21 154410.csv
./F1-ARCHIVE/F1-2012-05-08 190408.csv: Cannot stat: No such file or directory
tar: Exiting with failure status due to previous errors
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