Question

1

Script to find executable based on extension of a file?

rated 0 times [ 1] [ 0] / answers: 1 / hits: 760 / 1 Year ago, thu, november 24, 2022, 1:21:30

I need to create a script that returns the default app to be used for a given file extension (including the path). I had a look at the file command which can return the mime type and xdg-open which would open a file. But what I'd like to get is

myscript doc

/usr/bin/libreoffice

.or.

myscript fun

/opt/acme/roadrunner/meepmeep

How do I do that?

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answered 1 Year ago poous · Accepted Answer

I grabbed a Linux expert in the office and we found a reasonable solution:

#!/bin/bash

EXTENSION=$1

SAMPLENAME=$HOME/~webdavhelpersample.$EXTENSION

touch $SAMPLENAME

CURMINE=$(xdg-mime query filetype $SAMPLENAME)

rm $SAMPLENAME

CURDSK=$(xdg-mime query default $CURMINE)



if [ -f /.local/share/applications/$CURDSK ]; then

    TRUEDSK=/.local/share/applications/$CURDSK

elif [ -f /usr/local/share/applications/$CURDSK ]; then

    TRUEDSK=/usr/local/share/applications/$CURDSK

elif [ -f  /usr/share/applications/$CURDSK ]; then

    TRUEDSK=/usr/share/applications/$CURDSK

else 

    echo "Sorry no executable found for $1"

    exit 1

fi



WHATTODO=$(grep "^Exec" $TRUEDSK | head -1)

echo $WHATTODO

Once we figured that there are only 3 locations for the desktop files it was not hard anymore.