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rated 0 times [ 4] [ 0] / answers: 1 / hits: 487 / 2 Years ago, fri, july 22, 2022, 4:10:37

For example I have a directory:

/A/B/C/D/E/F/G.txt

Not knowing a priori /E/F/G.txt, I need to isolate that part. For ease of example:

echo '/A/B/C/D/E/F/G.txt' | grep -o '/A/B/C/D'

Shows:

/A/B/C/D

But I want:

/E/F/G.txt

With:

echo '/A/B/C/D/E/F/G.txt' | grep -o -v '/A/B/C/D'

I don't get the desired output (the output is not there at all).

How can I get the desired output using grep, i.e. not showing the part of the line which is in the search terms of grep?

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answered 2 Years ago whoppinolo · Accepted Answer

With PCRE expressions, you can specify a pattern but exclude it from the match using K:

% echo '/A/B/C/D/E/F/G.txt' | grep -Po '/A/B/C/DK.*'

/E/F/G.txt

However, if this is actually for files and directories, I'd suggest using find instead:

% mkdir -p A/B/C/D/E/F

% touch A/B/C/D/E/F/G.txt

% find A/B/C/D -type f -printf "%P

"

E/F/G.txt

Or if you really want the leading slash:

% find A/B/C/D -type f -printf "/%P

"

/E/F/G.txt

%P

File’s name with the name of the
command line argument under which it was found removed from the
beginning.