Question

4

Count number of files with specific extension(s) for each subdirectory

rated 0 times [ 4] [ 0] / answers: 1 / hits: 1852 / 2 Years ago, thu, june 23, 2022, 8:19:35

Source: Any directory tree with any number and type of files. Q: How many .jpg or .jpg and .png (for example) are in each subdirectory?

How can I limit the code below for files with 1 or more specific extension(s)? Having trouble inserting the -type f -name "*.jpg*", for example.

for DIR in $(find . -maxdepth 99 -type d)

do

    printf "%10d	%s

" $(find ${DIR}|wc -l) "${DIR}" 

done

Desired output:

118   ./aaa

 73   ./aaa/bbb

 16   ./aaa/bbb/ccc

If more than one file types are counted, then their combined total number in each subdirectories should be displayed.

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kroapathe

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answered 2 Years ago antoccasiona · Accepted Answer

Probably this find|xargs solution will work as you need.

find . -mindepth 1 -maxdepth 99 -type d -print0 | 

xargs -0 -i bash -c 'printf "%10d	%s

" "$(find "$1" -maxdepth 1 -type f -regextype awk -iregex ".*.(jpg|jpeg|png)" | wc -l)" "$1"' - '{}'

Some explanations:

The -mindepth 1 option is added in order to skip the current directory and process only the sub directories.

The -print0 provides the output entries with null delimiter, it works together with the -0 option of xargs.

The option - "{}" at the end will pass the xargs argument as value of the first positional parameter $1 of the bash command.

Within the second find command -iregex means case insensitive regular expression (you could use -regex instead).