Question

5

Extract mine only from file --mime-type to use in a if-else in bash script

rated 0 times [ 5] [ 0] / answers: 1 / hits: 699 / 3 Years ago, sun, august 1, 2021, 5:22:35

I have found that this command gives me the mime type from a file:

file --mime-type dog.jpeg

Output:

dog.jpeg: image/jpeg

I am now trying to create a bash checks if the mime is jpeg og png. However I am a bit stuck:

#!/bin/bash

$file_mime="file --mime-type dog.jpeg"

mime=`"${file_mime#*:}"`



if(mime=='image/jpg' OR mime=='image/png') do:

    echo"Jpg or png"

done

Output:

./bash.sh: line 2: =file --mime-type dog.jpeg: command not found

./bash.sh: line 3: : command not found

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learty

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answered 3 Years ago breadoules · Accepted Answer

Your first error is because you have a $ prefix on your assignment. Your second error is because you are trying to combine the execution of the command with the processing of the results (stripping the filename from the result). As always with bash scripting there are lots of ways to achieve the same thing so this is just one, try:

#!/bin/bash



mime=$(file -b --mime-type dog.jpeg)



if [[ $mime = image/@(jpeg|png) ]]; then

    echo "File is a jpeg or png."

fi

Then evaluate $mime but I suggest you search and read up on some bash scripting tutorials for if statements etc as your if statement is not valid bash script.