Question

4

replace text with part of text using regex with bash perl

rated 0 times [ 4] [ 0] / answers: 1 / hits: 2288 / 2 Years ago, mon, may 23, 2022, 9:15:15

For example I have this output:

string1 anynameveryveryverylong string2

string1 othernameveryveryverylong   string2

I want truncate the name to the first ten characters:

string1 anynamever  string2

string1 othernamev  string2

a pseudo regex can be:

perl -pe "s/([^	]+	)([^	]+)	/12{10}	/g"

How do i get this?

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answered 2 Years ago antorchestr · Accepted Answer

perl -pe 's/^(S+s+)(S{10})S*/$1$2/'

^ matches at the start of the string

S means non-whitespace

+ means repeated at least once

s means whitespace

{10} means repeated 10 times

I.e. Keep the first word and the first 10 characters of the following word while forgetting the remaining characters of the second word.

Your pseudoregex has one substantial problem: the {10} is placed in the replacement part, but the replacement is just a string. The regex happens in the pattern part only.