Question

2

Extract a date from a filename for CSH script?

rated 0 times [ 2] [ 0] / answers: 1 / hits: 889 / 2 Years ago, fri, may 20, 2022, 10:33:59

I am trying to write a CSH script that will look at components of the filename to generate a date/time. The problem is, I have no idea how to extract part of a filename to use it. Here is a sample filename:

nam_218_20140126_1800_001.grb

20140126 is the date portion of the filename and 1800 is the time. I need to extract it and convert it to 2014-01-26_18:00:00 for use in an environment variable. Any hints?

Thanks

Answers

Only authorized users can answer the question. Please sign in first, or register a free account.

rmiend

Add To Favorites

Follow

Total Points: 292

Total Questions: 101

Total Answers: 111

Location: Azerbaijan

Member since Tue, Aug 9, 2022

2 Years ago

rmiend questions

1 `apt-mark showmanual` shows almost all packages. messed up?

Sun, Nov 6, 22, 18:35, 2 Years ago

1 Failed opening required 'PhpMyAdmin/MoTranslator/autoload.php'

Wed, Sep 15, 21, 17:00, 3 Years ago

1 Suspend to RAM not working

Tue, Jan 18, 22, 23:52, 2 Years ago

1 Curl works, but not pages in a web browser with OpenLiteSpeed

Thu, Feb 24, 22, 09:48, 2 Years ago

1 How can I install latest version of Cinnamon in Ubuntu?

Sat, Sep 17, 22, 15:44, 2 Years ago

View All

answered 2 Years ago brellked · Accepted Answer

% set filename='nam_218_20140126_1800_001.grb' 

% set datetime=`echo "$filename" | sed -r 's/.*_([0-9]{4})([0-9]{2})([0-9]{2})_([0-9]{2})([0-9]{2}).*/1-2-3_4:5:00/'`

% echo $datetime

2014-01-26_18:00:00